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Keen: fill in the latin.c validator function.
This seems to make no difference that I can detect: a test generation run of the form 'keen --generate 1000 6du#12345' outputs an identical list of 1000 puzzle ids before and after. So the missing validation in this puzzle seems to have been benign.
This commit is contained in:
85
keen.c
85
keen.c
@ -591,9 +591,90 @@ static int solver_hard(struct latin_solver *solver, void *vctx)
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#define SOLVER(upper,title,func,lower) func,
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static usersolver_t const keen_solvers[] = { DIFFLIST(SOLVER) };
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static bool keen_valid(struct latin_solver *solver, void *ctx)
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static int transpose(int index, int w)
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{
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return true; /* FIXME */
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return (index % w) * w + (index / w);
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}
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static bool keen_valid(struct latin_solver *solver, void *vctx)
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{
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struct solver_ctx *ctx = (struct solver_ctx *)vctx;
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int w = ctx->w;
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int box, i;
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/*
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* Iterate over each clue box and check it's satisfied.
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*/
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for (box = 0; box < ctx->nboxes; box++) {
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int *sq = ctx->boxlist + ctx->boxes[box];
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int n = ctx->boxes[box+1] - ctx->boxes[box];
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long value = ctx->clues[box] & ~CMASK;
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long op = ctx->clues[box] & CMASK;
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bool fail = false;
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switch (op) {
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case C_ADD: {
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long sum = 0;
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for (i = 0; i < n; i++)
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sum += solver->grid[transpose(sq[i], w)];
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fail = (sum != value);
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break;
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}
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case C_MUL: {
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long remaining = value;
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for (i = 0; i < n; i++) {
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if (remaining % solver->grid[transpose(sq[i], w)]) {
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fail = true;
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break;
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}
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remaining /= solver->grid[transpose(sq[i], w)];
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}
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if (remaining != 1)
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fail = true;
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break;
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}
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case C_SUB:
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assert(n == 2);
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if (value != labs(solver->grid[transpose(sq[0], w)] -
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solver->grid[transpose(sq[1], w)]))
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fail = true;
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break;
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case C_DIV: {
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int num, den;
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assert(n == 2);
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num = max(solver->grid[transpose(sq[0], w)],
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solver->grid[transpose(sq[1], w)]);
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den = min(solver->grid[transpose(sq[0], w)],
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solver->grid[transpose(sq[1], w)]);
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if (den * value != num)
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fail = true;
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break;
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}
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}
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if (fail) {
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#ifdef STANDALONE_SOLVER
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if (solver_show_working) {
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printf("%*sclue at (%d,%d) is violated\n",
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solver_recurse_depth*4, "",
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sq[0]/w+1, sq[0]%w+1);
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printf("%*s (%s clue with target %ld containing [",
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solver_recurse_depth*4, "",
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(op == C_ADD ? "addition" : op == C_SUB ? "subtraction":
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op == C_MUL ? "multiplication" : "division"), value);
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for (i = 0; i < n; i++)
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printf(" %d", (int)solver->grid[transpose(sq[i], w)]);
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printf(" ]\n");
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}
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#endif
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return false;
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}
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}
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return true;
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}
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static int solver(int w, int *dsf, long *clues, digit *soln, int maxdiff)
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