latin_solver_alloc: handle clashing numbers in input grid.

In the setup phase of the centralised latin.c solver, we start by
going over the input grid containing already-placed clue numbers, and
calling latin_solver_place to enter each on into the solver's data
structure. This has the side effect of ruling out each number from the
rest of the row and column, and _also_ checking by assertion that the
number being placed is not ruled out.

Those are a bad combination, because it means that if you give an
obviously inconsistent input grid to latin_solver_alloc (e.g. with two
identical numbers in a row already), it will fail an assertion. In
that situation, you want the solver run as a whole to return
diff_impossible so that the error is reported cleanly.

This assertion failure could be provoked by giving either Towers or
Group a manually-constructed game description inconsistent in that
way, and hitting Solve. Worse, it could be provoked during live play
in Unequal, by filling in a number clashing with a clue and then
pressing 'h' to get hints.
This commit is contained in:
Simon Tatham
2023-02-05 10:29:42 +00:00
parent 517b14e666
commit 5030d87903
4 changed files with 60 additions and 41 deletions

47
latin.c
View File

@ -563,7 +563,7 @@ void latin_solver_free_scratch(struct latin_solver_scratch *scratch)
sfree(scratch);
}
void latin_solver_alloc(struct latin_solver *solver, digit *grid, int o)
bool latin_solver_alloc(struct latin_solver *solver, digit *grid, int o)
{
int x, y;
@ -577,14 +577,23 @@ void latin_solver_alloc(struct latin_solver *solver, digit *grid, int o)
memset(solver->row, 0, o*o);
memset(solver->col, 0, o*o);
for (x = 0; x < o; x++)
for (y = 0; y < o; y++)
if (grid[y*o+x])
latin_solver_place(solver, x, y, grid[y*o+x]);
#ifdef STANDALONE_SOLVER
solver->names = NULL;
#endif
for (x = 0; x < o; x++) {
for (y = 0; y < o; y++) {
int n = grid[y*o+x];
if (n) {
if (cube(x, y, n))
latin_solver_place(solver, x, y, n);
else
return false; /* puzzle is already inconsistent */
}
}
}
return true;
}
void latin_solver_free(struct latin_solver *solver)
@ -810,15 +819,17 @@ static int latin_solver_recurse
} else {
newctx = ctx;
}
latin_solver_alloc(&subsolver, outgrid, o);
#ifdef STANDALONE_SOLVER
subsolver.names = solver->names;
#endif
ret = latin_solver_top(&subsolver, diff_recursive,
diff_simple, diff_set_0, diff_set_1,
diff_forcing, diff_recursive,
usersolvers, valid, newctx,
ctxnew, ctxfree);
if (latin_solver_alloc(&subsolver, outgrid, o))
ret = latin_solver_top(&subsolver, diff_recursive,
diff_simple, diff_set_0, diff_set_1,
diff_forcing, diff_recursive,
usersolvers, valid, newctx,
ctxnew, ctxfree);
else
ret = diff_impossible;
latin_solver_free(&subsolver);
if (ctxnew)
ctxfree(newctx);
@ -1059,11 +1070,13 @@ int latin_solver(digit *grid, int o, int maxdiff,
struct latin_solver solver;
int diff;
latin_solver_alloc(&solver, grid, o);
diff = latin_solver_main(&solver, maxdiff,
diff_simple, diff_set_0, diff_set_1,
diff_forcing, diff_recursive,
usersolvers, valid, ctx, ctxnew, ctxfree);
if (latin_solver_alloc(&solver, grid, o))
diff = latin_solver_main(&solver, maxdiff,
diff_simple, diff_set_0, diff_set_1,
diff_forcing, diff_recursive,
usersolvers, valid, ctx, ctxnew, ctxfree);
else
diff = diff_impossible;
latin_solver_free(&solver);
return diff;
}